The wavelength of ${K_\alpha }$ line for an element of atomic number $29$ is $\lambda $ . Then the wavelength of ${K_\alpha }$ line for an element of atomic no $15$ is (Take mosley‘s constant $b = 1$ for both elements)
$\frac{{29}}{{15}}\lambda $
$\frac{{28}}{{15}}\lambda $
$4\lambda $
$2\lambda $
In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is
Hydrogen $(H)$, deuterium $(D)$, singly ionized helium $(H{e^ + })$ and doubly ionized lithium $(Li)$ all have one electron around the nucleus. Consider $n =2$ to $n = 1 $ transition. The wavelengths of emitted radiations are ${\lambda _1},\;{\lambda _2},\;{\lambda _3}$ and ${\lambda _4}$ respectively. Then approximately
What was the thickness of the gold foil kept in the Geiger-Marsden scattering experiment?
Orbital acceleration of electron is
What radioactive source did the Geiger and Marsden use in the scattering experiment?